thats so easy

3+7=x
(√3+√7i)(√3-√7i)=x
(√3+√7i)(√3-√7i)-x=0
(√3+√7i)(√3-√7i)-x=0
x((√3+√7i)(√3-√7i)/x-1)=0
idk how its called but its an equation produit nul which um. kinda means that (√3+√7i)(√3-√7i)/x-1=0 (it doesnt actually means that it means something else but i fucked up somewhere somehow but shh)
and so anyway we have
(√((√3+√7i)(√3-√7i)/x)-1)(√((√3+√7i)(√3-√7i)/x)+1)=0
(√((√3+√7i)(√3-√7i)/x))²+1×√((√3+√7i)(√3-√7i)/x)-1×√((√3+√7i)(√3-√7i)/x)-1²=0
(√3+√7i)(√3-√7i)/x-1=0
(√3+√7i)(√3-√7i)/x=1
(√3+√7i)(√3-√7i)=x
(√3)²+((√3)×(-√7i))+((√7i)×(√3))-(√7i)²=x
3-(-7)=x
3+7=x.
fuck.