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Pertanyaan selanjutnya, Akar-akar persamaan x2 + (a – 1)x + 2 = 0 adalah α dan b.Jika α = 2b dan a> 0 maka nilai a = ….
x2 + (a – 1)x + 2 = 0 adalah α dan b.
α = 2b
a> 0
Jadi gini,
a + b = - (a - 1) / 1
a + (a/2) = - a + 1
(3a/2) = -a + 1
3a = -2a + 2
3a + 2a = 2
5a = 2
a = 2/5
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